- 相關(guān)推薦
C語(yǔ)言基礎(chǔ)算法案例(精選)
C語(yǔ)言的設(shè)計(jì)目標(biāo)是提供一種能以簡(jiǎn)易的方式編譯、處理低級(jí)存儲(chǔ)器、產(chǎn)生少量的機(jī)器碼以及不需要任何運(yùn)行環(huán)境支持便能運(yùn)行的編程語(yǔ)言。下面整理了一些C語(yǔ)言基礎(chǔ)算法案例,希望對(duì)大家有所幫助!
1、C語(yǔ)言打印一條語(yǔ)句
源代碼:
/* C Program to print a sentence. */
#include
int main()
{
printf("C Programming"); /* printf() prints the content inside quotation */
return 0;
}
輸出:
C Programming
2、C語(yǔ)言打印用戶輸入的一個(gè)整數(shù)
#include
int main()
{
int num;
printf("Enter a integer: ");
scanf("%d",&num); /* Storing a integer entered by user in variable num */
printf("You entered: %d",num);
return 0;
}
輸出:
Enter a integer: 25
You entered: 25
3、C語(yǔ)言實(shí)現(xiàn)兩個(gè)整數(shù)相加
/*C programming source code to add and display the sum of two integers entered by user */
#include
int main( )
{
int num1, num2, sum;
printf("Enter two integers: ");
scanf("%d %d",&num1,&num2); /* Stores the two integer entered by user in variable num1 and num2 */
sum=num1+num2; /* Performs addition and stores it in variable sum */
printf("Sum: %d",sum); /* Displays sum */
return 0;
}
輸出:
Enter two integers: 12
11
Sum: 23
4、C語(yǔ)言實(shí)現(xiàn)兩個(gè)小數(shù)相乘
/*C program to multiply and display the product of two floating point numbers entered by user. */
#include
int main( )
{
float num1, num2, product;
printf("Enter two numbers: ");
scanf("%f %f",&num1,&num2); /* Stores the two floating point numbers entered by user in variable num1 and num2 respectively */
product = num1*num2; /* Performs multiplication and stores it */
printf("Product: %f",product);
return 0;
}
輸出:
Enter two numbers: 2.4
1.1
Product: 2.640000
5、C語(yǔ)言查找字符的ASCII值
/* Source code to find ASCII value of a character entered by user */
#include
int main(){
char c;
printf("Enter a character: ");
scanf("%c",&c); /* Takes a character from user */
printf("ASCII value of %c = %d",c,c);
return 0;
}
輸出:
Enter a character: G
ASCII value of G = 71
6、C語(yǔ)言根據(jù)用戶輸入的整數(shù)做商和余數(shù)
/* C Program to compute remainder and quotient */
#include
int main(){
int dividend, divisor, quotient, remainder;
printf("Enter dividend: ");
scanf("%d",÷nd);
printf("Enter divisor: ");
scanf("%d",&divisor);
quotient=dividend/divisor; /* Computes quotient */
remainder=dividend%divisor; /* Computes remainder */
printf("Quotient = %d ",quotient);
printf("Remainder = %d",remainder);
return 0;
}
輸出:
Enter dividend: 25
Enter divisor: 4
Quotient = 6
Remainder = 1
7、C語(yǔ)言獲取整型、單精度浮點(diǎn)型、雙精度浮點(diǎn)型和字符型的長(zhǎng)度
基本語(yǔ)法:
/* This program computes the size of variable using sizeof operator.*/
#include
int main(){
int a;
float b;
double c;
char d;
printf("Size of int: %d bytes ",sizeof(a));
printf("Size of float: %d bytes ",sizeof(b));
printf("Size of double: %d bytes ",sizeof(c));
printf("Size of char: %d byte ",sizeof(d));
return 0;
}
輸出:
Size of int: 4 bytes
Size of float: 4 bytes
Size of double: 8 bytes
Size of char: 1 byte
8、C語(yǔ)言獲取關(guān)鍵字long的長(zhǎng)度范圍
#include
int main(){
int a;
long int b; /* int is optional. */
long long int c; /* int is optional. */
printf("Size of int = %d bytes ",sizeof(a));
printf("Size of long int = %ld bytes ",sizeof(b));
printf("Size of long long int = %ld bytes",sizeof(c));
return 0;
}
輸出:
Size of int = 4 bytes
Size of long int = 4 bytes
Size of long long int = 8 bytes
9、C語(yǔ)言交換數(shù)值
#include
int main(){
float a, b, temp;
printf("Enter value of a: ");
scanf("%f",&a);
printf("Enter value of b: ");
scanf("%f",&b);
temp = a; /* Value of a is stored in variable temp */
a = b; /* Value of b is stored in variable a */
b = temp; /* Value of temp(which contains initial value of a) is stored in variable b*/
printf(" After swapping, value of a = %.2f ", a);
printf("After swapping, value of b = %.2f", b);
return 0;
}
輸出:
Enter value of a: 1.20
Enter value of b: 2.45
After swapping, value of a = 2.45
After swapping, value of b = 1.2
10、C語(yǔ)言檢查數(shù)值是奇數(shù)還是偶數(shù)
/*C program to check whether a number entered by user is even or odd. */
#include
int main(){
int num;
printf("Enter an integer you want to check: ");
scanf("%d",&num);
if((num%2)==0) /* Checking whether remainder is 0 or not. */
printf("%d is even.",num);
else
printf("%d is odd.",num);
return 0;
}
輸出1:
Enter an integer you want to check: 25
25 is odd.
輸出2:
Enter an integer you want to check: 12
12 is even.
也可以用條件運(yùn)算符解決:
/* C program to check whether an integer is odd or even using conditional operator */
#include
int main(){
int num;
printf("Enter an integer you want to check: ");
scanf("%d",&num);
((num%2)==0) ? printf("%d is even.",num) : printf("%d is odd.",num);
return 0;
}
【C語(yǔ)言基礎(chǔ)算法案例】相關(guān)文章:
10個(gè)經(jīng)典的C語(yǔ)言面試基礎(chǔ)算法及代碼10-06
C語(yǔ)言面試的10個(gè)經(jīng)典基礎(chǔ)算法及代碼09-16
c語(yǔ)言的排序算法07-22
C語(yǔ)言基本算法09-09
C語(yǔ)言面試中10個(gè)經(jīng)典的基礎(chǔ)算法及代碼10-21
c語(yǔ)言排序的幾種算法10-16
C語(yǔ)言奇偶排序算法08-05
最常用的c語(yǔ)言算法07-18