新GRE數(shù)學(xué)考試有哪些重要考點(diǎn)
考生在備考新GRE考試時(shí)，有必要知道一些重要的考點(diǎn)是關(guān)于新GRE的數(shù)學(xué)部分的。下面我們就來看看新GRE數(shù)學(xué)考試的.幾大重要考點(diǎn)，歡迎大家閱讀!
新GRE數(shù)學(xué)的重要考點(diǎn)：并集和交集
Intersection of Sets
Intersection of two sets is another set with only the members that are in both sets. If the two sets do not share any common member, the intersection is the empty set with no member.
Example:
Intersection of {1,2,3} and {2,3,5} is the set {2,3}.
Intersection of the set with all primes and the set with all even numbers is the set {2} since only 2 is both even and prime.
Intersection of {1,2,3} and {4,5,6} is the empty set {}.
Remember:
Intersection contains only the common members.
Two sets are disjoint if they have no member in common, that is they have an empty intersection.
Union of Sets
Union of two sets is another set with all the members from both sets.
Example:
Union of {2,3,5} and {1,3,4} is the set {1,2,3,4,5}.
Union of {1,2,1} and {1,2} is the set {1,2,1}.
Remember:
The common members do not repeat in the union.
新GRE數(shù)學(xué)的重要易錯(cuò)題
1. n個(gè)數(shù)從小到大排列，求(n-1)/4，設(shè)商為i，余數(shù)為j ,則可求得1st Quartile為：(第i+1個(gè)數(shù))*(4-j)/4+(第i+2個(gè)數(shù))*j/4
2. 4個(gè)*，2個(gè)·的排列方式 15(=)
3 .5雙襪子，同時(shí)去2只，剛好配對(duì)的概率。1/9
4. 40人說French,60人說Russian,80人說Italy,說兩種語(yǔ)言的有50人，說三種語(yǔ)言的有 10人. 共有125人,問不說這些語(yǔ)言的有幾人。Key：125-(40+60+80-50-10*2)=15
5 .等腰直角三角形邊長(zhǎng)2加2倍根號(hào)2，求面積。
6. 某種溶液濃度為125gram per liter, 轉(zhuǎn)換成 ounce per gallon,求表達(dá)式.已知 1 ounce=28.xxx gram and 1
gallon=3.875 liter
7. x,y,z 均方差為d, 求x+10,y+10,z+10的均方差 (d)
8. 1的概率是0.8,2的概率是0,6,問是1或是2或是both的概率,1-0.6*0.8(數(shù)字瞎編)=0.92.
9. 還有一組測(cè)量數(shù)據(jù)中,12.1比mean低1.5個(gè)標(biāo)準(zhǔn)差,17.5比mean高3.0個(gè)標(biāo)準(zhǔn)方差.問mean是多少.13.9(設(shè)標(biāo)準(zhǔn)差為X 12.1+1.5X=M，17.5-3X=M)
10. 圖表題,1992年總和是50,96年是60,每年至少增長(zhǎng)1,問最大的年增長(zhǎng)：7.0
GRE數(shù)學(xué)考試重點(diǎn)術(shù)語(yǔ)
2^5=the fifth power of 2
abscissa 橫坐標(biāo)
ordinate 縱坐標(biāo)
quadrant 象限
coordinate 坐標(biāo)
slope 斜率
intercede 截距(有正負(fù)之分)
solution (方程的)解
arithmetic progression 等差數(shù)列(等差級(jí)數(shù))
an=an+(n-1)d s=1/2(a1+an)
common divisor 公約數(shù)
common factor 公因子
least common multiple 最小公倍數(shù)
composite numbe 合數(shù)
prime factor 質(zhì)因子
prime number 質(zhì)數(shù)
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